Calculator

Transmon qubit

Select two independent parameter groups to solve the single-junction transmon in the usual large EJ/EC approximation.

Circuit

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CJJ

Inputs

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EJ group
EC group
ω01
ratio

Hamiltonian

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H^T=4EC(n^ng)2EJcosφ^\hat{H}_{\rm T}=4E_C\left(\hat{n}-n_g\right)^2-E_J\cos\hat{\varphi}

Formulas

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Constants

ϕ0=2e=3.29106×1016Wb\phi_0=\frac{\hbar}{2e}=3.29106\times10^{-16}\,{\rm Wb}
ΔAl=180μeV\Delta_{\rm Al}=180\,\mu{\rm eV}

Josephson group

EJ=ϕ0Ic=ϕ02LJE_J=\phi_0 I_c=\frac{\phi_0^2}{L_J}
IcRn=πΔAl2e=282.743μVI_cR_n=\frac{\pi\Delta_{\rm Al}}{2e}=282.743\,\mu{\rm V}

Charging group

EC=e22CE_C=\frac{e^2}{2C}

Transmon solve

EmEJ+8ECEJ(m+12)EC12(6m2+6m+3)E_m\simeq-E_J+\sqrt{8E_CE_J}\left(m+\frac{1}{2}\right)-\frac{E_C}{12}\left(6m^2+6m+3\right)
ωge8ECEJEC\hbar\omega_{ge}\simeq\sqrt{8E_CE_J}-E_C
αEC\alpha\simeq-E_C

Uses the Al/AlOx/Al Ambegaokar-Baratoff conversion from Scientific Reports 13, 6772 (2023) and ΔAl = 180 µeV from Nature Communications 13, 7196 (2022).

Result

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ParameterValueNumericalUnit

Advanced

ParameterValueNumericalUnit

Charge dispersion

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ng (Em - E0(0))/h (GHz)
ω01 num
α num
ε01